Creating a Simple Spring Web Application

The below procedure will help you to create your own web application

Pre-requiste:

You need an IDE(eg.Eclipse,RAD,NetBean etc) and java installed in your system.

Follow the below procedure to create using Eclipse IDE:

1) Create a Dynamic Web Project in your eclipse.
2) Configure your web.xml according to your need. The bellow is the given basic web.xml

        xmlns="http://java.sun.com/xml/ns/j2ee"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
                            http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
   simple-security

       simple-form
       org.springframework.web.servlet.DispatcherServlet
       1
   
  
   
       simple-form
       *.html
   
  
   
       index.jsp
   

3) The name of the dispatcherServlet is simple-form.
4) You need to configure the list of pages that you are going to visit in the dispatcherServlet.
5) The below is the simple configuration:

      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
      xmlns:p="http://www.springframework.org/schema/p"
      xmlns:aop="http://www.springframework.org/schema/aop"
      xmlns:tx="http://www.springframework.org/schema/tx"     
      xsi:schemaLocation="http://www.springframework.org/schema/beans 
              http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
              http://www.springframework.org/schema/aop 
              http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
         http://www.springframework.org/schema/tx 
         http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">

indexController



class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />


class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />

6) Create a index.jsp. Hence your web application has been created.